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Author Question for everybody
Paul_J
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Registered: 6th Jun 02
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24th May 06 at 21:41   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by Paul_J
quote:
Originally posted by Paul_J
quote:
Originally posted by Paul_J
quote:
Originally posted by SVM 286
The imperative is that a factor opposing the craft, is in equilibrium to it's own generated force.

This will prevent the vehicle from progressing from a geographical stand point.


Where the factor that is supplying an equal force to the thrust?


dave17
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24th May 06 at 21:41   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286
If the plane was hovering, of course it could make progress.




It basically is though mate, as the wheels have no friction, they are just spinning beneath.

Im not ganging up on u either mate, just trying to help you see it would take off
Paul_J
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24th May 06 at 21:41   View User's Profile U2U Member Reply With Quote

Get the message? What is holding the 26400 (the force) of the plane pushing forward at a standstill?
Ian
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24th May 06 at 21:41   View Garage View User's Profile U2U Member Reply With Quote

quote:
Originally posted by dave17
You could have the plane engines OFF, and the treadmill be going alone at 500mph and the plane would just stay in the SAME spot, would not move backwards.
Thats not strictly true, as in this instance the movement of the ground would have some effect. Its just not particularly difficult to overcome it once you turn on the engine.
Jules S
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24th May 06 at 21:42   View Garage View User's Profile U2U Member Reply With Quote

seems everybody has quoted me almost word for word in the last few pages from my posts in earlier pages

The long and short of it is.

For the plane not to take off the conveyor would have to be spherical and envelop the whole planet.

the conveyor would also have to be able to negate all the thrust propelled by the engines.... Ie force about 26k's worth of thrust backwards into the jets...

getting it yet?
Paul_J
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24th May 06 at 21:42   View User's Profile U2U Member Reply With Quote

If you put 26400 lb ft of force against a wall, it'd probably punch straight through the wall... So how is the conveyour belt which is not being gripped, as the wheels are just rolling over it - supplying a equal force in the opposite direction to the plane to hold it still?
Ian
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24th May 06 at 21:43   View Garage View User's Profile U2U Member Reply With Quote

Yes but the 200mph head wind would matter.

The belt does not.

You keep telling me that the belt and plane are travelling at the same speed. I'm telling you repeatedly that the belt doesn't matter.

Really, it doesn't.
Paul_J
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24th May 06 at 21:43   View User's Profile U2U Member Reply With Quote

Is that the sound of it clicking in svn's head?
dave17
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24th May 06 at 21:44   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286

It's geographically stationary Paul - Correct

It makes no physical headway through the surrounding air and as such attains no ground speed - Incorrect, all it has to do is turn up the power on the engines

Because of this it cannot attain lift and cannot take off - It can travel forwards as fast as it needs to go, enough to generate the lift
Ian
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24th May 06 at 21:45   View Garage View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286
It's geographically stationary Paul.
In order for it to be stationary, the forces must be equal.

In order for the forces to be equal, the wheels must cause as much drag as the thrust creates.

This is not the case.
SVM 286
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24th May 06 at 21:45   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by Paul_J
quote:
Originally posted by SVM 286
The imperative is that a factor opposing the craft, is in equilibrium to it's own generated force.

This will prevent the vehicle from progressing from a geographical stand point.


Where the factor that is supplying an equal force to the thrust?


Not thrust Paul, SPEED.

The belt is moving under the craft at the same speed as the craft in the opposing direction.

If you were to stand on the tarmac next to the conveyor and watch the plane, it would be static from your perspective, but the surface of the belt would rush past you the same way it would from the perspective of a passenger.
jr
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24th May 06 at 21:46   View User's Profile U2U Member Reply With Quote

SVM, he's right (ian that is)

Robin
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24th May 06 at 21:46   View Garage View User's Profile U2U Member Reply With Quote

if the answer to the last two questions id like that dave, the first one must be incorrect
dave17
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24th May 06 at 21:46   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by Ian
quote]Thats not strictly true, as in this instance the movement of the ground would have some effect. Its just not particularly difficult to overcome it once you turn on the engine.


ok maybe not 500mph, as im sure the bearings are not completely friction free past a point, but at a lower speed, im sure it could be at a standstill due to the weight of the plane. And as you say, it would need very little force to keep it on the spot if the belt speed was increased
Paul_J
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24th May 06 at 21:47   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286
quote:
Originally posted by Paul_J
quote:
Originally posted by SVM 286
The imperative is that a factor opposing the craft, is in equilibrium to it's own generated force.

This will prevent the vehicle from progressing from a geographical stand point.


Where the factor that is supplying an equal force to the thrust?


Not thrust Paul, SPEED.

The belt is moving under the craft at the same speed as the craft in the opposing direction.

If you were to stand on the tarmac next to the conveyor and watch the plane, it would be static from your perspective, but the surface of the belt would rush past you the same way it would from the perspective of a passenger.


Jesus christ. NO IT WOULDN'T

An equilbreum is 2 EQUAL FORCES. Speed is not a force, SPEED is a measurement of DISTANCE covered by TIME.

THRUST IS A FORCE.

RESISTANCE / DRAG IS A FORCE.

THEY MUST BE EQUAL FOR PLANE NOT TO MOVE.
Jules S
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24th May 06 at 21:47   View Garage View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286
quote:
Originally posted by Paul_J
quote:
Originally posted by SVM 286
The imperative is that a factor opposing the craft, is in equilibrium to it's own generated force.

This will prevent the vehicle from progressing from a geographical stand point.


Where the factor that is supplying an equal force to the thrust?


Not thrust Paul, SPEED.

The belt is moving under the craft at the same speed as the craft in the opposing direction.

If you were to stand on the tarmac next to the conveyor and watch the plane, it would be static from your perspective, but the surface of the belt would rush past you the same way it would from the perspective of a passenger.


read my post above mate...
Ian
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24th May 06 at 21:47   View Garage View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286
Not thrust Paul, SPEED.
Speed is a product of force that way minus force the other way.

One is a fuck off big engine, the othre is some frictionless wheels.

While its possible to balance the two, the engine would win.
dave17
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24th May 06 at 21:47   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by robmarriott
if the answer to the last two questions id like that dave, the first one must be incorrect


eh?
Robin
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24th May 06 at 21:50   View Garage View User's Profile U2U Member Reply With Quote

you said that it was geographically stationary, agreeing with SVM, but for that to be true, you'd need to change the answer in the other two bits of the quote....
Steve
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24th May 06 at 21:50   View Garage View User's Profile U2U Member Reply With Quote

is svm the only one arguing this now?
Paul_J
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24th May 06 at 21:51   View User's Profile U2U Member Reply With Quote

yup

He thinks if 2 things go at each other at the same speed they will be equal, regardless of forces, masses etc
dave17
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24th May 06 at 21:51   View User's Profile U2U Member Reply With Quote

No, the plane is stationary when it is at low power. When the plane turns the power up, it is free to make its way down the belt and take off.
SVM 286
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24th May 06 at 21:51   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by Ian
Yes but the 200mph head wind would matter.

The belt does not.

You keep telling me that the belt and plane are travelling at the same speed. I'm telling you repeatedly that the belt doesn't matter.

Really, it doesn't.


It does Ian.

It wouldn't if the plane had taken off but it hasn't so it does matter.

Aircraft need lift to take off.

If the 'ground' beneath the plane is advancing towards it at an equal speed, then the plane cannot attain speed in relation to the surrounding air to produce the lift required for take-off.

This is the point people are missing.

You HAVE to have X ammount of wind speed/pressure on the wings of an aircraft for it to take off unless it is a Harrier of a helicopter.
Ian
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24th May 06 at 21:53   View Garage View User's Profile U2U Member Reply With Quote

I'm clear that lift is required.

I'm more concerned with how your stationary plane stays stationary when the forces acting on it are so imbalanced.
Paul_J
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24th May 06 at 21:53   View User's Profile U2U Member Reply With Quote

quote:
Originally posted by SVM 286
You HAVE to have X ammount of wind speed/pressure on the wings of an aircraft for it to take off unless it is a Harrier of a helicopter.


I think SVN thinks we're all idiots.

I can imagine him sitting there quite smug. I think I met this guy at grasshopper he seemed a decent chap. Just can't believe he can't see what is staring him in the face.

In our scenerio the plane is moving - NOT standing still like in your head.

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