You're using a round bracket instead of a curly one to close the if.

You also shouldn't be escaping the final quote in the first echo statement, or indeed the first quote in th second echo.

And the concatonation is to pot, I assume you're trying to substitute variables in to whats printed by the echo?

You might want to consider something like:

code:


if ($page == 1) {

 echo "<a href='?page=" . $page+1 . "'>Next</a>";

}

else {

 echo "<a href='?page=" . $page-1 . "'>Previous</a>";

 echo "<a href='?page=" . $page+1 . "'>Next</a>";

}

or even

echo "<img src=\"$page.jpg\">";

To be honest would make it easier to read if you did:

echo "<img src='$page.jpg'>";

Shouldn't
echo "<img src="$page.jpg">;
be
echo "<img src=\"$page.jpg\">;

?

pls pls dudes

any1 for this 1???

it worked but i got more probs :(

Parse error: parse error, expecting `','' or `';'' in /users/ionichost.com/photochops/chopperszine/index.php on line 4

code:


<? if(file_exists("images/$page.jpg")){ echo "<img src="$page.jpg">; } else { 

echo "Error 404 <b>$page.jpg</b> not found. Please report to <A href=\"mailto:groombros@aol.com\"> webmaster</A>" ;} ?>

OK let me know if I was right! :)

thx so much m8 ill get bk 2 u

I think it should look like this mate:

<?if ($page=="1") {echo "<a href=\"?page=$page + \"1\"\">Next </a>" ) else { echo \"<a href=\"?page=$page - \"1\"\">Back </a>\" \"<a href=\"?page=$page + \"1\"\">Next </a>";}?>

Hi mate, I don't know alot of PHP but I do know a few web languages:

<?if ($page=="1") {echo "<a href=\"?page=$page + \"1\"\">Next </a>\" ) else { echo \"<a href=\"?page=$page - \"1\"\">Back </a>\" \"<a href=\"?page=$page + \"1\"\">Next </a>";}?>

I think the prob lies after your first </a>, get rid of the \ before the " as this tells it to print a special character, the character being the speech mark. Whereas you don't want to print the speech mark, just use it to denote the end of your string.

PLEASE!!!!!

plz, i need it done asap

Sorry groom :lol: ;)

I know php... but fk it... too late

stfu:P

Echoooooooooooooooooooooo

and yes i no 1.jpg is not there i not care bout that its after webmaster that it went rong

i get this as output and its not wot i want now


Error 404 1.jpg not found. Please report to webmasterNext " ) else { echo "Back " "Next

ah i think i got it, ill update soon

why do i get a parse error in this line of code???

code:
<?if ($page=="1") {echo "<a href=\"?page=$page + \"1\"\">Next </a>\" ) else 

{ echo \"<a href=\"?page=$page - \"1\"\">Back </a>\" \"<a href=\"?page=$page + \"1\"\">Next </a>";}?>